(iii) (x2 – 2x)2 – 23(x2 – 2x) + 120.
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Hi,
(x² - 2x)² - 23(x² - 2x) + 120
Let a = x² - 2x
=a² - 23a + 120
= a² -15a - 8a + 120
= a(a - 15 ) - 8 ( a - 15 )
= (a - 15 )( a - 8)
=(x² - 2x - 15) (x² - 2x - 8)
= [x2 + 3x - 5x - 15 ] (x² -4x + 2x - 8)
= [X (x + 3) - 5 (x+3) ] [ x (x - 4) + 2(x =
- 4)]
= (x+3)(x - 5)(x-4) (x + 2)
= (x - 5)(x-4) (x + 2) (x + 3)
I hope this helps you.
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