(iii) (x2 – 9xy + 5y) – (3x²y – y2 + 7xy) + y - xy - Sy - 2)
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Step-by-step explanation:
Add the following expressions:
(i) x3−2x2y+3xy2−y3, 2x3−5xy2+3x2y−4y3
(ii) a4−2a3b+3ab3+4a2b2+3b4,−2a4−5ab3+7a3b−6a2b2+b4
ANSWER:
Adding the given expressions, we have
(i) x3- 2x2y + 3xy2- y3+ 2x3- 5xy2 + 3x2y- 4y3
Collecting positive and negative like terms together, we get
x3+ 2x3- 2x2y + 3x2y + 3xy2- 5xy2 - y3 - 4y3
= 3x3 + x2y - 2xy2 - 5y3
(ii) (a4- 2a3b + 3ab3 + 4a2b2 + 3b4) + (-2a4- 5ab3 + 7a3b - 6a2b2 + b4)
a4- 2a3b + 3ab3 + 4a2b2 + 3b4 - 2a4- 5ab3 + 7a3b - 6a2b2 + b4
Collecting positive and negative like terms together, we get
a4 - 2a4 - 2a3b + 7a3b + 3ab3 - 5ab3 + 4a2b2 - 6a2b2 + 3b4 + b4
= - a4 + 5a3b - 2ab3 - 2a2b2 + 4b4
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