Question

IIIULIU.
11. Find the value of p, if the distance between the points(4, p) and (1, 0) is 5 units.​

Answer 1

using, the formula =distance formula

let A=(4,p) here, x1=4,Y1=p

letB=(1, 0) here, X2=1,Y2=0

AB=5

AB^2 =(x2-x1)^2 + (Y2-Y1)^2

5^2 =(1-4)^2 + (0-p)^2

25=(-3)^2 +(-p) ^2

25=9+p^2

25-9=p^2

16=p^2

Applying root both side

root16=rootp^2

4=p

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