Question

iin triangle abc De parallel to BC find value of x ad= x db=x+1 ae=x+3 ec =x+5​

Answer 1

Step-by-step explanation:

Step 1:

Triangle ABA, DE || BC, so by Basic Proportionality theorem,  

AD / DB = AE / EC

Step 2:

Substituting the values, we get,

x / x - 2 = x + 2 / x - 1

Step 3:

By cross multiplying, we get,

X (x - 1) = ( x + 2) ( x - 2)

x^2

- x =

x^2

- 4

x = 4  

Answer 2

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Step 1:

Triangle ABA, DE || BC, so by Basic Proportionality theorem,

AD / DB = AE / EC

Step 2:

Substituting the values, we get,

x / x - 2 = x + 2 / x - 1

Step 3:

By cross multiplying, we get,

X (x - 1) = ( x + 2) ( x - 2)

x^2 - x = x^2 - 4

x = 4