[IIT 2011]
d²x/dy² is equal to
(a) -(d²y/dx²)^-1 (dy/dx)^-3
(b) (d²y/dx²) (dy/dx)^-2
(c) -(d²y/dx²)(dy/dx)^-3
(d) (d²y/dx²)-1
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Answered by
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Hi !!
[Option 'c' is correct option ] -(d²y/dx²)(dy/dx)^-2
Solution is in this given
attachment
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I hope this will helps you !!
@Raj❤ ✔
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Answered by
1
Step-by-step explanation:
Given,
d²y/dx²
= (d/dy)[dx/dy)
= (d/dx)[dx/dy] * dx/dy
= d/dx[1/dy/dx] * dx/dy
= (-dx/dy²) * d²y/dx² * dx/dy
= (1/dy/dx)³ * d²y/dx²
Hope it helps!
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