Question

[IIT 2011]

d²x/dy² is equal to

(a) -(d²y/dx²)^-1 (dy/dx)^-3

(b) (d²y/dx²) (dy/dx)^-2

(c) -(d²y/dx²)(dy/dx)^-3

(d) (d²y/dx²)-1 ​

Answer 1

Hi !!

[Option 'c' is correct option ] -(d²y/dx²)(dy/dx)^-2

Solution is in this given

attachment

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I hope this will helps you !!

@Raj❤ ✔

Answer 2

Step-by-step explanation:

Given,

d²y/dx²

= (d/dy)[dx/dy)

= (d/dx)[dx/dy] * dx/dy

= d/dx[1/dy/dx] * dx/dy

= (-dx/dy²) * d²y/dx² * dx/dy

= (1/dy/dx)³ * d²y/dx²

Hope it helps!