Question

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Answer 1

Answer:

$\huge\underline\pink{\tt Hey\:Mate}$

Erms = 220 V

Frequency = 50 Hz

(a) Erms = Eo/✓2

Eo= Erms ✓ 2 => ✓ 2 × 220

Eo= 1.414 ×220

Eo = 311.08

Eo = 311 V

(b) Time taken for the current to reach the peak value = time taken to reach the 0 value from rms

I= Io/✓ 2

I= I0sinwt

wt = π/4

t= π/4w

t=π/4×2πf

t= π/8π50

t= 1/1400

t= 2.5 ms

Hope it helps uh!!!

Answer 2

Answer:

$\huge\underline\bold\orange{Answer}$

Given :-

Erms = 220

Frequency = 50Hz

$\huge{\boxed{\mathcal Erms=\frac{Eo}{\sqrt{2}}}}$

$\large{\mathcal Eo=Erms{\sqrt{2}}}$

$\large{\mathcal Eo={\sqrt{2}×200}}</p><p>$

$\large{\mathcal Eo=1.414×220}</p><p>$

$\huge{\boxed{\mathcal Eo=311 V}}$

Time taken for the current to reach the peak value =time taken to reach 0 value from rms

$\large{\mathcal I={\frac{Io}{\sqrt{2}}}}$

$\large{\mathcal I=Iosinwt}$

$\large{\mathcal wt={\frac{π}{4w}}}</p><p>$

$\large{\mathcal t={\frac{π}{4×2πf}}}$

$\large{\mathcal t={\frac{π}{1400}}}</p><p>$

$\huge{\boxed{\mathcal t=2.5ms}}</p><p>$

@14riyaz14