Question

iit question solve it​

Answer 1

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HERE'S THE ANSWER ✌

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$<I>font color="blue"></p><p>Heat required to melt 50 gram of ice =mL=50*80=4000 cal</p><p>Heat given out by water in cooling from 80°Celsius to 0° celsius =mC∆T=50*1*80=4000 cal</p><p>Heat given by water is just sufficient to melt the whole ice.So the final temperature is 0°celsius .$

Answer 2

Answer;

See the attached file!

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