इज इक्वल टू 1 प्लस साइन एक्स वाई वन माइनस कॉस एक्स प्लस साइन एक्स वेयर इज इक्वल
Answers
Answer:
The proof is explained step-wise below :
Step-by-step explanation:
To prove : sin²θ + cos²θ = 1
Proof :
In a triangle using sine rule we know that :
\sin\theta=\frac{Perpendicular}{Hypotenuse}\\\\\implies \sin^2\theta= \frac{Perpendicular^2}{Hypotenuse^2}........(1)\\\\\cos\theta=\frac{Base}{Hypotenuse}\\\\\implies \cos^2\theta= \frac{Base^2}{Hypotenuse^2}......(2)\\\\\text{Now, adding (1) and (2)}\\\\\implies \sin^2\theta+\cos^2 \theta =\frac{Perpendicular^2}{Hypotenuse^2} + \frac{Base^2}{Hypotenuse^2} \\\\\implies \sin^2\theta+\cos^2 \theta =\frac{Perpendicular^2+Base^2}{Hypotenuse^2}\\\\\implies \sin^2\theta+\cos^2 \theta =\frac {Hypotenuse^2}{Hypotenuse^2}\\\\\implies \sin^2\theta+\cos^2 \theta =1
Explanation:
Theta is written as A
To prove : sin^2A + cos^2A
===================
Proof :
We know, sin^2 A = \frac{height^2}{hyotenuse^2} \\ \\cos^2 A = \frac{base^2}{hypotenuse^2}
Then,
sin^2 A + cos^2 A
\frac{height^2}{hypotenuse^2} + \frac{base^2}{hypotenuse^2} \\ \\ \frac{height^2 + base^2}{hypotenuse^2} \\ \\ \frac{hypotenuse^2}{hypotenuse^2} \\ \\ 1
Hence, Proved.
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