ik 1-sin2A÷cos2A = tan2A then find the value of thita
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1-sin2A/cos 2A=tan2A
(sin2A +cos2A =1;cos2A =1-sin2A)
cos2A /cos2A =tan2A
1=tan2A
1=tanA
(tan45°=1)
A=45°
may it help U
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