Question

Iliana multiplied 3p – 7 and 2p2 – 3p – 4. Her work is shown in the table. Which is the product? 6p3 + 23p2 + 9p + 28 6p3 – 23p2 – 9p + 28 6p3 – 23p2 + 9p + 28 6p3 + 23p2 – 9p + 28

Answer 1

Hello

let us multiply (3p-7)(2p^2-3p-4)

6p^3-9p^2-12p-14p^2+21p+28

rearranging

6p^3-23p^2+9p+28

this is the answer

thanks

Answer 2

Answer:

(c)  6p³ - 23p² + 9p +28

Step-by-step explanation:

(3p -7)(2p² - 3p -4)

= 6p³ - 9p² - 12p - 14p² + 21p +28

Grouping like terms together

= 6p³ - 23p² + 9p +28

∴ (3p -7)(2p² - 3p -4) = 6p³ - 23p² + 9p +28

Hence the answer is (c)  6p³ - 23p² + 9p +28