ilIf the value of 2x + 3Y= 16.and xy = 8. find 4x^2+9y^2
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Answered by
4
Answer:
Step-by-step explanation:
2x+3y=8 xy=4
4x2+9y2= (2x)^2+(3y)^2
=(2x+3y)^2-2×2x×3y
= (2x+3y)^2-12 xy
=(8)^2-12×4
=64-48
=16
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Answered by
2
Answer:
(2x-3y) ^2=4x^2+9y^2-12xy
(16) =4x^2+9y^2-12*8
4x^2+9y^2=16+96
4x^2+ 9y^2=112
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