Question

Illustrate in the complex plane the set of points satisfying the condition Z-3|=4​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let Z = x+yi

So,

Z-3= x+yi+3 = (x-3) +yi

|Z-3| =

$\sqrt{ {(x - 3)}^{2} + {y}^{2} }$

Therefore,

$\sqrt{ {(x - 3)}^{2} + {y}^{2} } = 4 \\ {(x - 3)}^{2} + {y}^{2} = {4}^{2}$

It is an equation of circle with centre as (-3,0) and radius 4 unit.

Thus all the points on the circumference of circle is the set of points satisfying the given condition.