Question

Illustration 14: Consider an object moving with an initial velocity of 10 m/s and
acceleration of 2 m/s2. Find distance travelled from t = 0 to 6 s. ​

Answer 1

Answer:

initial velocity, u = 10 m/s

acceleration, a = 2 m/s2

time, t = 6 sec

Let finAL velocity be v

so

$\: as \: we \: know \: \: \: s = ut + \frac{1}{2} a {t}^{2} where \: s \: is \: the \: distance \\ s = 10 \times 6 + \frac{1}{2} \times 2 \times 6 \times 6 \\ s = 60 + \frac{1}{2} \times 72 \\ s = 60 + 36 \\ s = 96$

So the distance is 96 m