Question

Illustration 3.24 A bird flies due east through a distance of
100 m, then heading due north by a distance of 50 m, it flies
vertically up through a distance of 20 m. Find the position of
the bird relative to its initial position.​

Answer 1

Answer:

the position of  the bird relative to its initial position is 100 $\hat{i}$  + 50 $\hat{j}$ + 20  $\hat{k}$ m

Explanation:

Given data

distance  east  = 100 m

distance north = 50 m

distance vertical = 20 m

to find out

position of  the bird

solution

we know bird first fly in east than north and then vertical up side

so we consider here

east is x axis i.e $\hat{i}$ , y is north axis i.e $\hat{j}$  and z is vertical up side i.e $\hat{k}$

we consider bird initial position is o and final position is R

so final position are $\vec{R}$ = x $\hat{i}$  + y $\hat{j}$ + z  $\hat{k}$

so put here x, y and z

$\vec{R}$ = 100 $\hat{i}$  + 50 $\hat{j}$ + 20  $\hat{k}$

so  the position of  the bird relative to its initial position is 100 $\hat{i}$  + 50 $\hat{j}$ + 20  $\hat{k}$ m