Math, asked by armanmehta, 10 months ago


ILLUSTRATIVE EXAMPLES
EXAMPLE1 Express the following decimals in the form
(I) 0.32(bar is on 2)
(ii) 0.123(bar is on 3
(I) 0.00352(bar is on 2)

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Answers

Answered by aman240292
5

(i) 0.32 = (32-3)/90 =29/90

How did I do ?

Lets see the denominator first..

Decimal ke bad jitne bhi no. bar ke niche hai unke liye 9 likho ...0.32 me sirf ek no. niche h to 9 likha....fir jitne number bina bar k niche hai utne hi 0 likho 9 k aage....yha sirf ek no. hi hai...to ek zero aagya....aisa krke denominator aagya 90.

Lets come to numerator portion now...

Decimal ke bad jitne bhi number hai wo as it is likho....0.32 me 32 hai to 32 likha.

Then ab decimal k bad jo bhi number bina bar ke hai unhe minus kr diya...32 me 3 bina bar ke hai...to isliye numerator aagya 32-3 =29

and denominator =90

So 29/90

Try doing other sums..and feel free to contact .


aman240292: ok
aman240292: 15.712 =15 +0.712
aman240292: 0.712 = (712-7)/990
aman240292: 15+705/990
aman240292: (990×15+705)/990
armanmehta: no by the method you taught me before
aman240292: 15555/990=5185/330
armanmehta: give answer by your previous method
aman240292: method is same bro
armanmehta: ok thanks
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