Question

Im = 1
16. Find the radius of the base of the cylinder if
(1) its volume is 2310 cm and height is 15 cm.
(11) its volume is 15400 cm and height is 25 cm.
3
6.6​

Answer 1

Answer:

$1)\pi {r}^{2} h = 2310 \\ \frac{22}{7} {r}^{2} \times 15 = 2310 \\ {r}^{2} = \frac{2310 \times 7}{22 \times 15} \\ {r}^{2} = 49 \\ r = 7 \\ 11) \: same \: as \: 1$

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

1,VOLUME OF CYLINDER =2310cm^3

HEIGHT OF THE CYLINDER =15cm

RADIUS =???

VOLUME OF CYLINDER=pie×r^2×h

2310=pie×r^2×15

2310=22/7×15×r^2

2310/1=22/7×15× r^2. cross multiply

2310×7÷22×15 ===r^2

by simplyfing,

r^2=7×7

r=7cm.

2,VOLUME OF CYLINDER =15400cm^3

HEIGHT OF THE CYLINDER =25cm

RADIUS =???

VOLUME OF CYLINDER=pie×r^2×h

15400=pie×r^2×25

pie×r^2=15400/25=616

r^2×22/7=616/1. cross multiply

by symplifying,

r^2=392÷2

r^2=196

r=_/196

r=14cm