Question

Im a building there are some humans(2 legs each) thrice as many dogs (4 legs each)and some number of spiders(8legs each) if there are 50legs in the total how many spiders are there

Answer 1

Given :  there are some humans(2 legs each) thrice as many dogs (4 legs each)and some number of spiders(8legs each)

To find :   how many spiders are there

Solution:

Let day dogs = D

Number of legs of Dogs = 4D

Human thrice as many Dogs

=> Human = 3D

=> Legs of Human =  2 * 3D  = 6D

Total number of legs of Dogs & Human = 4D + 6D   = 10D

Let say Spider =  S

Number of spider legs = 8S

8S + 10D  = 50

8S must end with 0  as all other terms are ending with zero

Hence Either

Spider = 0  or   5

as its given some spiders hence we ignore 0 ,

Spider  = 5  , Dogs = 1  Human = 3

5 Spiders are there

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