Im ∆ABC, D and E are points on the sides. ABand AC respectively AD = 3.9cm, DB = 3 cm, AE = 2.6cm FindEC
Answers
Answered by
6
Answer:
In a Δ ABC, D and E are points on the sides AB and AC respectively such that DE || BC.
i) If AD = 6 cm, DB = 9 cm and AE = 8 cm, Find AC.
Solution:
Given: Δ ABC, DE ∥ BC, AD = 6 cm, DB = 9 cm and AE = 8 cm.
Required to find AC.
By using Thales Theorem, [As DE ∥ BC]
AD/BD = AE/CE
Let CE = x.
So then,
6/9 = 8/x
6x = 72 cm
x = 72/6 cm
x = 12 cm
∴ AC = AE + CE = 12 + 8 = 20.
Answered by
0
Answer:
see down there is explained answer
Step-by-step explanation:
Answer
(i) Given : DE∥BC in △ ABC,
Using Basic proportionality theorem,
∴
DB
AD
=
EC
AE
⇒
3
1.5
=
EC
1
⇒EC=
1.5
3
EC=3×
15
10
=2 cm
EC=2 cm.
(ii) In △ABC,DE∥BC (Given)
Using Basic proportionality theorem,
∴
DB
AD
=
EC
AE
⇒
7.2
AD
=
5.4
1.8
⇒AD=1.8×
5.4
7.2
=
10
18
×
10
72
×
54
10
=
10
24
⇒AD=2.4cm
So, AD=2.4 cm
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