im the first term and common difference of am arithematice sequence are equal find the relation between 5th term and 10th term
Answers
Answered by
1
Step-by-step explanation:
First term of the sequence is 10 and common difference is 3.
a
1
= 10 and d = 3
Next term = a
2
=a
1
+d=10+3=13
a
3
=a
2
+d=13+3=16
Thus, first three terms of the sequence are 10, 13 and 16.
Let 100 be the nth term of the sequence.
a
n
=a
1
+(n−1)d
100=10+(n−1)3
90=(n−1)3
n−1=30
n=31, which is a whole number.
Therefore, 100 is the 31
st
term of the sequence.
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Answered by
0
Answer:
10 th term - twice of 5 th term
Step-by-step explanation:
first term a=common difference d sorry
fifth term t5= a+( n,,-1<,)d
,=+(5-1)d
=a+
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