Question

image
3) An object 2 cm is size infront of a concave
missor of focal length 15 cm and forms
object Kept at a distance of toom from
it Find the position nature and size of the Image
formed by it
of an
an​

Answer 1

Answer:

• Height of the object =2 cm

• U(object distance) = -15 as u is always negative

• F = -10 (as it is always negative for concave miror and lens )

• $1/F =1/v + 1/u \\ </li></ul><h3></h3><ul><li>-1/10 = 1/v + (-1/15) \\ </li></ul><h3></h3><ul><li>-1/10 +1/15 =v \\ </li></ul><h3></h3><ul><li>-3+2/30 =v \\ </li></ul><h3></h3><ul><li>V=-30cm</li></ul><h3></h3><ul><li>$

$</p><ul><li>Hi/Ho = - V/U \\ </li></ul><p></p><ul><li>Hi /2 = -(-30/15) \\ </li></ul><p></p><ul><li>Hi =-30×2÷15 \\ </li></ul><p></p><ul><li>Hi =-4cm (Real \: and \: inverted)</li><li>.$

$hope \: its \: help \: u$

Answer 2

Answer

• Height of the object =2 cm

• U(object distance) = -15 as u is always negative

• F = -10 (as it is always negative for concave miror and lens )

$1/F =1/v + 1/u \\ -1/10 = 1/v + (-1/15) \\ -1/10 +1/15 =v \\ -3+2/30 =v \\ V=-30cm</p><p></p><p> </p><p> </p><p>Hi/Ho = - V/U \\ Hi /2 = -(-30/15) \\ Hi =-30×2÷15 \\ Hi =-4cm (Real \: and \: inverted)</p><p>$

Hope it helps u ..... ¿