Physics, asked by nithiyapriya1914, 1 year ago

Image formed by a concave mirror is real and twice the size of the object .calculate magnification of the mirror

Answers

Answered by UrFirstLove1
11

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Answered by rishkrith123
0

Answer:

The magnification of the concave mirror is -2.

Explanation:

Given,

The height of the image(h_v) formed by a concave mirror is real and twice the height of the object(h_o).

i.e. h_v = 2h_o

To find,

The magnification of the concave mirror.

Concept,

The magnification (m) of a concave mirror is given by:

m = \frac{h_v}{h_o}

Where,

h_v is the height of the image obtained by the concave mirror.

h_o is the height of the object placed in front of the concave mirror.

Calculation,

h_v = -2h_o (As for a concave mirror if the image is real, then the image will be inverted, so down the principle axis the height is negative)

Hence,

m = \frac{-2h_o}{h_o}

⇒ m = -2

Therefore, the magnification of the concave mirror is -2.

#SPJ2

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