Imagine a ball travelling in deep space.There are no stars planets around to compare its motions to .How would we know that that the ball is in motion/isnt travelling at all? in other words what is time? and for that matter what is space ?
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This is a longstanding problem in physics and has not been wholly solved to anyone's satisfaction. It's not just rotational motion, any motion is subject to this concern. Very basically, what is "motion" for a singular object in its own universe?
Mach was one of the first to really explore this issue. He spoke of masses in deep space and wondered if they would have momentum. He concluded they had to, and then went looking for potential solutions to the obvious problem of the lack of any sort of universal ruler.
He concluded that the mass distribution of the universe as a whole (which at that time was the Milky Way remember) forms a sort of momentum background against which all objects, local or no, actually measure against. So even in the case when you're studying the collision of objects on a billiard table, the momentum you measure isn't relative to the table, it's "really" relative to this universal frame, but in the end the table is to so you can reduce it that way.
A more direct solution to the problem was offered by Brans-Dicke theory. This is a theory that is very similar to General Relativity in that it ascribes many things, notably gravity, to the geometry of spacetime. However, it also adds a second linear field that is sort of "baked into" the universe when it is created. This field creates a background reference frame for momentum.
So if BD theory is correct, yes, a universe with a single object in it will definitely feel angular momentum.
Unfortunately, as far as we can tell, BD is wrong. There is no direct evidence of this, but it falls to Occam's Razor. The issue is that BD has a coupling constant (alpha IIRC) that defines how strongly this other field couples to the spacetime - its basically similar to G in normal GR. As it falls to zero, the theory becomes GR in the same sort of way that Newtonian gravity is the weak-field limit of GR.
You can measure alpha indirectly, and to date every new measurement forces it ever closer to zero.
In physics, spacetime is any mathematical model that fuses the three dimensions of space and the one dimension of time into a single four-dimensional continuum. Spacetime diagrams can be used to visualize relativistic effects such as why different observers perceive where and when events occur.
hope it helps
pls mark brainliest
here is your answer
This is a longstanding problem in physics and has not been wholly solved to anyone's satisfaction. It's not just rotational motion, any motion is subject to this concern. Very basically, what is "motion" for a singular object in its own universe?
Mach was one of the first to really explore this issue. He spoke of masses in deep space and wondered if they would have momentum. He concluded they had to, and then went looking for potential solutions to the obvious problem of the lack of any sort of universal ruler.
He concluded that the mass distribution of the universe as a whole (which at that time was the Milky Way remember) forms a sort of momentum background against which all objects, local or no, actually measure against. So even in the case when you're studying the collision of objects on a billiard table, the momentum you measure isn't relative to the table, it's "really" relative to this universal frame, but in the end the table is to so you can reduce it that way.
A more direct solution to the problem was offered by Brans-Dicke theory. This is a theory that is very similar to General Relativity in that it ascribes many things, notably gravity, to the geometry of spacetime. However, it also adds a second linear field that is sort of "baked into" the universe when it is created. This field creates a background reference frame for momentum.
So if BD theory is correct, yes, a universe with a single object in it will definitely feel angular momentum.
Unfortunately, as far as we can tell, BD is wrong. There is no direct evidence of this, but it falls to Occam's Razor. The issue is that BD has a coupling constant (alpha IIRC) that defines how strongly this other field couples to the spacetime - its basically similar to G in normal GR. As it falls to zero, the theory becomes GR in the same sort of way that Newtonian gravity is the weak-field limit of GR.
You can measure alpha indirectly, and to date every new measurement forces it ever closer to zero.
In physics, spacetime is any mathematical model that fuses the three dimensions of space and the one dimension of time into a single four-dimensional continuum. Spacetime diagrams can be used to visualize relativistic effects such as why different observers perceive where and when events occur.
hope it helps
pls mark brainliest
generalRd:
mark brainliest plz
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