Imagine a clock where the hour hand makes only one revolution in 1 day (i.e., 24 hr) whereas the minute hand completes one revolution in one hour. What is the angle between the two hands at 14:50 hr as per this clock?
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Solution:-
As this a special clock so, this clock will have digits from 1 to 24 i.e. 24 numbers marked. The measure of angle between two consecutive digits = 360°/24 = 15°.
Time taken by the minute hand to move from one digit to the other consecutive digit = 60 minutes/24 = 2.5 minutes.
At 14:50 hours, the hour hand will be at 14 and the minute hand will be at 20. So, the difference between these two digits = 20 - 14 = 6
Therefore,
The angle between the two hands at 14:50 hr = 6 × 15 = 90°
Answer.
As this a special clock so, this clock will have digits from 1 to 24 i.e. 24 numbers marked. The measure of angle between two consecutive digits = 360°/24 = 15°.
Time taken by the minute hand to move from one digit to the other consecutive digit = 60 minutes/24 = 2.5 minutes.
At 14:50 hours, the hour hand will be at 14 and the minute hand will be at 20. So, the difference between these two digits = 20 - 14 = 6
Therefore,
The angle between the two hands at 14:50 hr = 6 × 15 = 90°
Answer.
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77.5 degrees.Bec in a 24 hr clock each hr wud be of angle 360/24= 15 degrees. So first we take the angle between 15hrs and 20 hrs(since minute hand is 50mins which is at 20 hrs... check by drawing a clock) i.e. we calculate the angle for 5 hrs which is 5×15 = 75 degrees. Then we add the angle for 10 mins alone(since 15 hrs-10 mins wud be 14 hrs 50mins). To find angle for 10 mins we divide the degree of each hour by 60 mins and then multiply by 10 mins i.e. 15/60= 0.25 degrees. 0.25×10=2.5 degrees. Adding 2.5 degrees from 75 degrees we gave 77.5 degrees and that's your answe
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