Imagine a hard surface along xz plane to
be fixed. A particle moving along the line
4x + 3y – 12 = 0 with a speed of
10 m/s from the positive side of y–
axis, approaches towards the plane and
colloids. If the coefficient of restitution be
e = 0.75, then the speed of the particle
after collision is 2x m/s. Then’x?
value is
(A)
6
(C) 3
(D)
2.5
Answers
Answered by
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Given:
1. Equation of line: 4x + 3y – 12 = 0
2. Speed of particle = 10m/s
3. e = 0.75
To find:
Value of x
Solution:
- As per the question,
v sinϕ = u sinθ and v cosϕ = eu cosθ
- Therefore, v = u√(e² cos²θ+ sin²θ)
= 10√[(6.75)²(4/5)²+(3/5)²]
= 6√2
= 2(3√2) m/s
- Thus, the value of x = 3√2 m/s
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