Question

Imagine a person is travelling in a helicopter and drops an object of mass 3 kg
from an height of 1600 km above the surface of a planet A of mass 24 1810 kg
and radius 3200 km. Find its initial acceleration (Assume g=10 m/s2 give the
answer in two decimal place value)

Answer 1

Answer:

given

G= 6.67x10*-11 Nm*2/kg*2

R=3200km=3.2x10*6 m

M=3x10*24 kg

g=?

g=GM/R*2=(6.67x10*-11 Nm*2/kg*2 ).(3x10*24 kg) /(3.2x10*6 m)*2= 19.54 m/s*2

the acceleration due to gravity is 19.54 m/s*2

Explanation:

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Answer 2

Answer:

G= 6.67x10*-11 Nm*2/kg*2

R=3200km=3.2x10*6 m

M=3x10*24 kg

g=?

g=GM/R*2=(6.67x10*-11 Nm*2/kg*2 ).(3x10*24 kg) /(3.2x10*6 m)*2= 19.54 m/s*2

the acceleration due to gravity is 19.54 m/s*2