Question

Imagine that a reactor converts all given mass into energy and that it operates at a power level of 109 watt. The mass of the fuel consumed per hour in the reactor will be

Answer 1

Answer:

$4*10^{-2}gm$

Explanation:

Energy converted in one hour = $(p)(t)$

                                                   =$(10^{9}) (3600sec)$

                                                   =$(36)(10^{11}J)$

Mass of fuel consumed in one hour is

$M\frac{E}{c^{2} }$

$M=\frac{(36*10^{11}) }{(3*10^{8})^{2} }$

$M=4*5^{-5}kg=4*10^{-2}gm$