Question

Imagine we are throwing a five-sided die 50 times. On average, out of these 50 throws how many times would this five sided die show an odd number (e.g., 1, 3 or 5)?

Answer 1

total outcomes =5 (1,2,3,4,5,)

favour outcomes =3 (1,3,5)

p=3/5

n=number of trails =50

average =np =50×3/5=30 times

Answer 2

Answer:

This five sided die show an odd number 30 times out of 50.

Step-by-step explanation:

Consider the provided information.

We have a five sided die.

Therefore the total number of outcomes are: 1, 2, 3, 4, 5

Now the odd numbers are = 1, 3, 5

Here the total number of outcomes are 5 and favorable outcomes are 3.

Probability of Odd numbers = $\frac{3}{5}$

Expectation = $50\times \frac{3}{5}=30$

Hence, the expectation is 30.

Therefore, this five sided die show an odd number 30 times out of 50.