Imagine we are throwing a loaded die (6 sides). The probability that the die shows a 6 is twice as high as the probability of each of the other numbers. On average, out of these 70 throws how many times would the die show the number 6?
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Answer:
20
Step-by-step explanation:
die has six sides so probability of each is 1/6 but,
The probability that the die shows a 6 is twice as high as the probability of each of the other numbers.
so,
the probability of 6 is 2/7 and other,s probability is 1/7
we throws die 70 time
so probability 6 out of 70 throws is
=70*(2/7)
=20
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