Imagine you throw three hoops over these cone :30,90,40 .add together the number of each cone you get a hoop on. You have three throws a turn.What different totals can you make on each turn?
Answers
Given : throw three hoops over these cone :30,90,40
add together the number of each cone you get a hoop on
To Find : What different totals can you make on each turn?
Solution:
Assuming That always get hoop over a cone
3 x 3 x 3 = 27 cases
Possible sums
30 + 30 + 30 = 90 1 way
30 + 30 + 40 = 100 ( this can be in 3 Ways )
30 + 30 + 90 = 150 ( this can be 3 ways)
30 + 40 + 40 = 110 ( this can be in 3 ways)
30 + 40 + 90 = 160 ( this can be in 6 ways)
30 + 90 + 90 = 210 ( this can be in 3 ways)
40 + 40 + 40 = 120 1 way
40 + 40 + 90 = 170 ( this can be in 3 ways)
40 + 90 + 90 = 220 ( this can be in 3 ways)
90 + 90 + 90 = 270 1 way
Total 27 Ways
Possible sums in Order
( 90 , 100 , 110 , 120 , 150 , 160 , 170 , 210 , 220 , 270)
There are 10 different totals can be made
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