Question

img k beech vale k ans do plz

Answer 1

Answer:

OPT is right angled at P

sec30⁰ = OT/PT

$\frac{2}{ \sqrt{3} } = \frac{6 \sqrt{3} }{pt}$

$pt \: = \frac{6 \sqrt{3} \times \sqrt{3} }{2}$

PT = 9 units

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