immediate four digit number divisible afteer 4000 divisible by 3 4 5 leavs remainder 2
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Take the LCM of 3, 4, and 5.
3 x 4 x 5 = 60.
Let's take a look at the multiples of 60 near and after 4000.
4000 ÷ 60 gives remainder 40. 40 + 20 = 60.
So 4000 + 20 = 4020 is the multiple of 60 near and after 4000.
4020 is divisible by 3, 4 and 5. If 2 is left as remainder on division by 3, 4, and 5, then 2 should be added to 4020.
∴ 4020 + 2 = 4022 is the answer.
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