Math, asked by PREDATORXS, 1 year ago

(imp) Factories the above polynomial​

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Answered by sanketj
1

 \sqrt{2}  {x}^{2}  + 3x +  \sqrt{2} \\  =  \sqrt{2}   {x}^{2}  + 2x + x +  \sqrt{2}  \\  =  \sqrt{2} x(x +  \sqrt{2} ) + 1(x +  \sqrt{2} ) \\  = ( \sqrt{2}x  + 1)( x + \sqrt{2} )

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