Imperical formula of compound is Ch2o it's mol. Wt 90 Calculate the rf of the compound
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Let's start by finding the empirical formula mass of this compound:
CH2OCH2O= C + (2)H + O = 12.0 + 2(1.0) + 16.0= 30 grams per mole
12030=412030=4
Since the molar mass of the compound is four times the empirical formula mass, the molecular formula is four times the empirical formula:
4(CH2O)=C4H8O24(CH2O)=C4H8O2
CH2OCH2O= C + (2)H + O = 12.0 + 2(1.0) + 16.0= 30 grams per mole
12030=412030=4
Since the molar mass of the compound is four times the empirical formula mass, the molecular formula is four times the empirical formula:
4(CH2O)=C4H8O24(CH2O)=C4H8O2
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