Question

implify:
(cos 40° + i sin 40°) (cos 50° + i sin 50°)
(cos 50° + i sin 50°) (sin 50° + i cos 50°)
2(cos 95° + i sin 95%)
cos 35º + i sin 35°​

Answer 1

Answer:

We're asked to check whether a square pyramid, satisfying the following properties, really exists or not.

Since the square pyramid is made using a square of side 16 cm,

Length of base edge, \sf{a=16\ cm}a=16 cm

The triangle used to make has one side of length 16 cm, which should be attached to side of the square, so that the other sides of the triangle, measuring 10 cm each, should be slant edge of the square pyramid.

Length of slant edge, \sf{e=10\ cm}e=10 cm

Let's find the height of the square pyramid, \sf{h,}h, which is given by,

$\longrightarrow\sf{h=\sqrt{e^2-[(\dfrac{a}{2})^2+(\dfrac{a}{2})^2]}}$⟶h=

$\longrightarrow\sf{h=\sqrt{e^2-[\dfrac{a^2}{4}+\dfrac{a^2}{4}]}}$⟶h=

$\longrightarrow\sf{h=\sqrt{e^2-\dfrac{2a^2}{4}}}$⟶h=

$\longrightarrow\sf{h=\sqrt{e^2-\dfrac{a^2}{2}}}$⟶h=

Putting values of \sf{e}e and \sf{a,}a,

$\longrightarrow\sf{h=\sqrt{10^2-\dfrac{16^2}{2}}}$⟶h=

$\longrightarrow\sf{h=\sqrt{100-\dfrac{256}{2}}}$⟶h=

$\longrightarrow\sf{h=\sqrt{100-128}}$⟶h=

$\longrightarrow\sf{h=\sqrt{-28}\ cm}$⟶h=

Well, square root of a negative number is not real. This implies the square pyramid does not exist.

Hence, we can't make a square pyramid using square of side 16cm, and four triangles each with one side 16 cm and the other two sides of 10 cm each.

Answer 2

Answer:

I hope answer is helpful to us