Math, asked by ananyaahc, 5 hours ago

import time well rupees 8000 620 amount to Rupees 10344 at 10% per annum​

Answers

Answered by divyasingh016787
0

Answer:

Given:- P=Rs.8000,A=Rs.8368,R=6%

We know that,

Amount=Principal(1+((Rate×time)/100))

=(8360/8000)=1+((6×t)/100)

=(8360/8000)−1=((6×t)/100)

=t=[(8360−8000)/8000]×(100/6)

=(360/8000)×(100/6)

=(6/8)×12months

=9months

Answered by chaitanya6697
0

Answer:

Answer:

Given:- P=Rs.8000,A=Rs.8368,R=6%

We know that,

Amount=Principal(1+((Rate×time)/100))

=(8360/8000)=1+((6×t)/100)

=(8360/8000)−1=((6×t)/100)

=t=[(8360−8000)/8000]×(100/6)

=(360/8000)×(100/6)

=(6/8)×12months

=9months

Step-by-step explanation:

Hope it's helpful

please mark me as a brainlist answer please

Similar questions