Question

!IMPORTANT!
Solve the following equations:

5 v + 3 w = 11

4 v + 6 w = 16



2nd

Solve the following pair of equations:

9a + 2 b = 54

a + 2 b = 6


3rd


Solve:

10 a + 3 b = 12

3 a + 5 b = 20


Guys pls answer this i have a assessment

Answer 1

Answer:

Here, As per our given equation, The value of v is 1 and of w is 2.

Step-by-step explanation:

Here, As per our given question,

=1)=5v + 3w=11 -(1st)eq.

=4v + 6w=16 -(2nd)eq.

Now, On solving both equations by elimination method, we would multiply with 2 in eq. 1 and with 1 in eq. 2 and then subtract eq. 2 from eq. 1,

=10v + 6w=22

=-4v -6w=-16

After soving, we get,

=10v-4v=22-16

=6v=6

=v=6/6

=v=1

Now,by putting value of v in eq. 1,we get,

=5×(1) +3w=11

=3w=11-5

=3w=6

=w=6/3

=w=2

So, Here the value of v in the given equations is 1 and of w is 2.

(Other equations can be solved by applying the whole procedure of this question,

#Apply your mind).

Thank you.

Answer 2

Step-by-step explanation:

1st equation

20v +12w=44

20v+30w=80

Subtraction of this,

18w=36

w=2

V=1

2nd equation,

9a+2b=54

a+2b=6

Subtraction of equations

8a=48

a=6 b=0

3rd equation,

30a+9b=36

30a+50b=200

Subtraction of the equation

41b=164

b=4

a=0