Science, asked by raisulmbi, 7 months ago

Important Structures - Marshall's Acid (H2S2O8)
oxidation number of S ??​

Answers

Answered by doraemonfan
1

Answer:

Oxidation number of Sulphur is 6 is Marshall acid

Explanation:

Hope it will help

Jai Hind

Answered by Anonymous
0

Answer:

In H2S2O8 since 2 oxygen form peroxide linkage so the O.N. of Sulphur is 6 .

H2S2O8

= 2+2x+[-2]*6+[-1]*2

=2x-12

2x-12=0

2x=12

x=12/2

x=6.

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