Question

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$\sin(48) \times \sec(42) + \cos(48 \times \csc(42) ) = 2$

Answer 1

L. H. S. = Sin 48 × sec 42 + cos 48 × cosec 42

=> Sin ( 90 - 42 ) × sec 42 + cos 48 × cosec ( 90 - 48 )

=> cos 42 × sec 42 + cos 48 × sec 48

=> 1 + 1 =2

=> R. H. S.

HENCE , PROVED.