Question

Impure phosphine is combustible due to presence of

Answer 1

P2H4 is the answer .

thanks for looking.

Answer 2

Impure phosphine is combustible due to the presence of $P_2H_4$.

• Phosphine, $PH_3$ a simple phosphorus hydride, is a colorless, odorless, and highly toxic gas. It is a non-combustible gas. It burns at 150° in the air and gives $P_2O_5$.
• Whereas, impure phosphine contains $P_2H_4$ (diphosphane), a spontaneously flammable inorganic compound that makes it combustible and also gives it a foul smell.

Hence, we can conclude that $P_2H_4$ is the impurity in phosphine that makes it flammable.

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