Math, asked by manishasingh1505, 2 months ago

Imran got 20% increase in his salary at the end of 1st year.At the end of 2nd year he got an increase of 10%.If his present income is 19800, what was his income two years ago?*

Answers

Answered by Aakashkanojiya

Step-by-step explanation:

given , 1st year = 20 %

2nd year = 10 %

present income = 19800

solution

, 1st year = 19800 / 20 %

= 19800 x 20/100

= 198 x 20

1st year = 3960

2nd year = 19800 / 10 %

= 198 x 10

2nd year = 1980

imran got in 1st year salary is 3960 and 2nd year salary is 1980

Answered by kalimullahbaltistani

Answer:

Step-by-step explanation:

Given:

Current salary= 19800

1st year increase 20%

2nd increase 10%

We have to find salary two years ago

let x be the salary two years ago.

salary after 1st year increase @ 20% = x + x * 20/100= 120x / 100=6x / 5

salary after 2nd year increase @ 10% that is current salary= 6x/5 + 6x / 5* (10/100) =>6x/5+ 6x/5* 1/10 =19800

6x / 5 + 6x / 50 = 66x / 50 = 66x / 50=19800

so 66x/50 = 19800 = > x = 19800 /66 * 50 = 15000

salary two years ago was 15000

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plz solve these questions...

Imran got 20% increase in his salary at the end of 1st year.At the end of 2nd year he got an increase of 10%.If his present income is 19800, what was his income two years ago?*​

Answers

Imran got 20% increase in his salary at the end of 1st year.At the end of 2nd year he got an increase of 10%.If his present income is 19800, what was his income two years ago?*