Question

In 0.1 m aqueous solution of urea the mole fraction of urea is

Answer 1

Answer:

0.0176

Explanation:

moles of urea =given mass /molar mass = 6/60=0.1.

thus, mole fraction of 6g urea in 100 ml water=0.1/5.55+0.1=0.1/5.65=0.0176.

Answer 2

Given: $0.1m$ solution of urea.

To find: mole fraction of urea.

Step-by-step method:

Step 1 of 2

The number of moles are calculated by dividing given mass by molar mass.

$n=\frac{w}{M} \\0.1=\frac{w}{60} \\w=6g/mol$

Step 2 of 2

Calculating the mole fraction.

$X=\frac{moles of urea}{totalmoles}\\X=\frac{0.1}{5.55+0.1}\\\\X=0.1769$

The mole fraction of urea is $0.1769$.