Chemistry, asked by StrongGirl, 8 months ago

In 0.1 mole fraction glucose solution find % (w/w) of water in the sample (in nearest integer)​

Answers

Answered by Ekaro
7

Answer :

Mole fraction of glucose = 0.1

We have to find %(w/w) of water in the solution.

_________________________________

\circ\sf\:X_{Glucose}+X_{Water}=1

\circ\sf\:X_{Water}=1-0.1

\circ\bf\:X_{Water}=0.9

Therefore,

  • Moles of Water = 0.9
  • Moles of Glucose = 0.1

፨ Molar mass of Gulcose = 180g/mol

፨ Molar mass of water = 18g/mol

Mass of water in solution :

  • w₁ = moles × molar mass
  • w₁ = 0.9 × 18
  • w₁ = 16.2 g

Mass of glucose in solution :

  • w₂ = moles × molar mass
  • w₂ = 0.1 × 180
  • w₂ = 18 g

%(w/w) of water :

➝ %(w/w) = w₁ / (w₁ + w₂) × 100

➝ %(w/w) = 16.2/(16.2+18) × 100

➝ %(w/w) = 1620/34.2

%(w/w) = 47.36%

Answered by Atαrαh
7

Answer:

 \bigstar \purple{\boxed{\mathtt{\% \dfrac{w}{w}  =47.36}}}

Solution :

As per the given question ,

 \rightarrow \mathtt{X_g = 0.1 \:  mole }

we know that ,

 \rightarrow \mathtt{X_g  + X_w = 1}

 \rightarrow \mathtt{0.1 + X_w = 1}

 \rightarrow \mathtt{ X_w = 1 - 0.1}

\rightarrow \mathtt{ X_w =0.9}

___________________

moles of glucose = 0.1 moles

moles of water = 0.9 moles

we know that ,

 \star \boxed { \mathtt{n =  \dfrac{w}{mol.wt} }}

here ,

  • n = moles
  • w = weight
  • mol.wt = molecular weight _g

______________

Glucose :

\implies \mathtt{n_g =  \dfrac{w_g}{mol.wt_g} }

here ,

  • ng = moles of glucose=0.1
  • mol weight of glucose = 180 g

\implies \mathtt{w_g =  0.1 \times 180}

\implies \mathtt{w_g =  18 \: g }

______________

Water :

\implies \mathtt{n_w=  \dfrac{w_w}{mol.wt_w} }

here ,

  • ng = moles of glucose=0.9
  • mol weight of glucose = 18 g

\implies \mathtt{w_g =  0.9 \times 18}

\implies \mathtt{w_g =  16.2 \: g}

______________

we need to find % w / w of water in the sample

we know that ,

 \star \boxed { \mathtt{\% \dfrac{w}{w}  =  \dfrac{w_w}{w_g + w_w} \times 100 }}

 \implies\mathtt{\% \dfrac{w}{w}  =  \dfrac{16.2}{18+ 16.2} \times 100 }

\implies\mathtt{\% \dfrac{w}{w}  =  \dfrac{16.2}{34.2} \times 100 }

\implies\mathtt{\% \dfrac{w}{w}  =0.4736 \times 100}

\implies  \red{\boxed{\mathtt{\% \dfrac{w}{w}  =47.36}}}

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