In 0.1 mole fraction glucose solution find % (w/w) of water in the sample (in nearest integer)
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Answered by
7
Answer :
Mole fraction of glucose = 0.1
We have to find %(w/w) of water in the solution
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Therefore,
- Moles of Water = 0.9
- Moles of Glucose = 0.1
፨ Molar mass of Gulcose = 180g/mol
፨ Molar mass of water = 18g/mol
◈ Mass of water in solution :
- w₁ = moles × molar mass
- w₁ = 0.9 × 18
- w₁ = 16.2 g
◈ Mass of glucose in solution :
- w₂ = moles × molar mass
- w₂ = 0.1 × 180
- w₂ = 18 g
◈ %(w/w) of water :
➝ %(w/w) = w₁ / (w₁ + w₂) × 100
➝ %(w/w) = 16.2/(16.2+18) × 100
➝ %(w/w) = 1620/34.2
➝ %(w/w) = 47.36%
Answered by
7
Answer:
Solution :
As per the given question ,
we know that ,
___________________
moles of glucose = 0.1 moles
moles of water = 0.9 moles
we know that ,
here ,
- n = moles
- w = weight
- mol.wt = molecular weight _g
______________
Glucose :
here ,
- ng = moles of glucose=0.1
- mol weight of glucose = 180 g
______________
Water :
here ,
- ng = moles of glucose=0.9
- mol weight of glucose = 18 g
______________
we need to find % w / w of water in the sample
we know that ,
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