Question

In 0.1 sec. a partical gose from point A to point B moving in a semicircle of radius 1.0m the magnitude of average speed is

Answer 1

partical gose from point A to point B moving in a semicircle of radius 1.0m

So the particle covers a distance equal to the arc of semicircle.

distance = πR = 3.142 × 1 = 3.142m

time taken = 0.1 s

Average speed = distance/time = 3.142/0.1 = 31.42 m/s

hence, average speed is 31.42 m/s

Answer 2

Answer:

Average Speed = Total Distance Covered / Total Time Taken

Total Distance Covered = Arc Length of Semicircle

Arc Length = $\dfrac{ \theta}{360} \times 2 \pi r$

=> Arc Length = $\dfrac{180}{360} \times 2 \times 3.14 \times 1$

=> Arc Length = 6.28 / 2 = 3.14 m

Hence Total Distance = 3.14 m

Total Time = 0.1 second

=> Average Speed = 3.14 / 0.1 = 31.4 m/s

Hence the average speed of the particle is 31.4 m/s.