Question

In 0.1m aqueous solution of urea the mole fraction of urea is

Answer 1

so moles of urea =given mass /molar mass = 6/60=0.1. thus, mole fraction of 6g urea in 100 ml water=0.1/5.55+0.1=0.1/5.65=0.0176.

Answer 2

Answer:

Mole fraction of urea is 0.0176.

Explanation:

Given Mol fraction of urea is 0.1

Now

$\frac{Mole of urea}{total \: mole} = \frac{1}{10}$

Let mole of urea be 1

Then mole of water is 9

Weight of water is

$9 \times 18 = 162 \: g = 0.162 \: g$

We know,

$Molality \: = \frac{mole \: of \: solute}{weight \: of \: solvent \: in \: kg} = \frac{1}{0.162} = 6.17$

Now,

$mole \: fraction = \frac{given \: mass}{molar \: mass} = \frac{0.1}{5.55 + 0.1} = 0.0176$

Required answer is 0.0176