Question

In 0.5 seconds,a projectile goes from 0
to 300 m/s.What is the acceleration of the projectile?

Answer 1

Answer:600m/s^2

Explanation:a=vf-vi/t

a=300-0/0.5

a=300/0.5

a=600m/s

Answer 2

The acceleration of the projectile is 600 $m/s^{2}$.

Given,

Initial velocity, u = 0 m/s

Final velocity, v = 300 m/s

Time taken for acceleration = 0.5 seconds.

To find,

the acceleration.

Solution:

v = u + at

300 = 0 + 0.5a

300 - 0 = 0.5a

300 = 0.5a

a = 300/0.5

a = 600 $m/s^{2}$.

The acceleration of the projectile comes to be 600 $m/s^{2}$.

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