Question

In 1.0 second a particle goes from point A to B moving in a semicircle of radius 1.0 m. The magnitude of average velocity is

Answer 1

Velocity = displacement / time
Here, displacement is equal to 2m and time is 1 second
So, velocity = 2m/1sec.
= 2m/s

Answer 2

Displacement = Shortest Distance between initial and final position.
When it travels a semicircular path then it’s displacement is equal to diameter of circle i.e 2r
Therefore displacement = 2 × 1 m = 2 m

Average velocity = Displacement / Time
= 2 m / 1 s
= 2 m/s

Average velocity of particle is 2 m/s