In 1 gram mixture of k2co3 and khc03 mass fraction
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A
96%K
2
CO
3
,4%Li
2
CO
3
Molecular weight of K
2
CO
3
=39×2+12+48=138g mol
−1
Equivalent weight of K
2
CO
3
=
2
138
=69g
Molecular weight of Li
2
CO
3
=7×2+12+48=74g mol
−1
Equivalent weight of Li
2
CO
3
=
2
74
=37g
Let, x g of K
2
CO
3
and (0.5−x) g of Li
2
CO
3
mEq K
2
CO
3
+ mEq of Li
2
CO
3
= mEq of HCl
(
69
x
+
37
0.5−x
)×1000=30×0.25
69×37
37x+69(0.5−x)
=
1000
30×0.25
69×0.5=
1000
30×0.25×69×37
=32x
34.5−19.14=32x
32x=15.36 and x=0.48
% of K
2
CO
3
=
0.5
0.48×100
=96%
% of Li
2
CO
3
=4%
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