Question

In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%
10%?
(a) 1 kg
(b) 200 gms
(c) 800 gms
(d) 1.8 kg
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Answer 1

Answer:

In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%? x = 1000 gms. So you need to add 1000 gm (or 1 kg) sand to the original mixture to get the proportion of iron as 10% in the new mixture.

Step-by-step explanation:

hope this will help you...

Answer 2

Answer:

1kg mixture contain sand and iron

total percentage of mixture=100%=1000gm

iron =20%=1000*(20/100)=200gm

sand=100-20=80%=1000*(80/100)=800gm

sand =1000-800=200gm.

we need to add 200gms of sand to make proportion of iron as10%