Question

IN 1 POT THE RATIO OF MILK AND WATER IS 3:5 AND IN ANOTHER POT IT IS 6:1. IN WHAT RATIO SHOULD THE CONTENTS OF THE TWO POTS BE MIXED SO AS TO MAKE THE RATIO RATIO BETWEEN MILK AND WATER 7:3​

Answer 1

Answer:

Pot 1: Ratio M/W = 3/5 -> 3 parts milk, 5 parts water

Pot 2: Ratio M/W = 6/1 -> 6 parts milk, 1 part water

Let f = the amount of pot 1 used

Let g = the amount of pot 2 used

The mixture contains a ratio of milk to water of 7/3 -> 7 parts milk, 3 parts water

So we need 3f parts milk + 6g parts milk to make 7 parts milk

So we need 5f parts water + g parts water to make 3 parts water

3f + 6g = 7

5f + g = 3 -> g = 3 - 5f

3f + 6(3 - 5f) = 7

27f = 11 -> f = 11/27

Thus g = 3 - 5*11/27 = (81 - 55)/27 = 26/27

So f/g = (11/27)/(26/27) = 11/26

So pot 1 to pot 2 = 11:26

Answer 2

Answer:

Pot 1: Ratio M/W = 3/5 -> 3 parts milk, 5 parts water

Pot 2: Ratio M/W = 6/1 -> 6 parts milk, 1 part water

Let f = the amount of pot 1 used

Let g = the amount of pot 2 used

The mixture contains a ratio of milk to water of 7/3 -> 7 parts milk, 3 parts water

So we need 3f parts milk + 6g parts milk to make 7 parts milk

So we need 5f parts water + g parts water to make 3 parts water

3f + 6g = 7

5f + g = 3 -> g = 3 - 5f

3f + 6(3 - 5f) = 7

27f = 11 -> f = 11/27

Thus g = 3 - 5*11/27 = (81 - 55)/27 = 26/27

So f/g = (11/27)/(26/27) = 11/26

So pot 1 to pot 2 = 11:26

Step-by-step explanation:

respect thug life