Question

In 10 complete rotations, the distance moved on the linear scale is 1 cm. There are 100 divisions on circular scale. When the gap AB is just closed, the 95th division of circular scale coincides with the reference line. While measuring the diameter of a wire, the linear scale reads 2 mm and 45th division on the circular scale coincides with the reference line. Find cross-sectional area of the wire.
(a) 3.8 cm2
(b) 0.049 cm?
(c) 0.098 cm?
(d) 0.45 cm2​

Answer 1

Answer:

Least count =

$\frac{1mm}{100} = .01mm$

Diameter = M. S. +( No. of division coinciding with main scalex Least count.)

= 1 mm + 47 x 0.01 mm

= 1.47 mm = 0.147 cm.

Curved surface area = πdL =

$\frac{22}{7}$

1.47* 5.6 -2.6cm²

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Answer 2

Answer:

and here is your answer friend

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